Dear Daisuke,
thank you for your question. We would propose the following workflow to estimate the shell thickness:
Assume you have core-shell particles of a base material (MaterialID 01) and a shell material (MaterialID 02). Then we propose the following workflow:
- Reassign the base material to a liquid material. The example structure may now look as in the following picture.
[ IMAGE NOT SHOWN - GUESTS CANNOT VIEW ATTACHED IMAGES ] - Use "Analyze -> Grain Find -> Estimate Grain Diamters" to estimate the coating thickness.
- “Estimate Grain Diameters” uses internally the Euclidian Distance Map, a watershed algorithm is used to transfer the values of voxels with small components to neighboring voxels with large components
- We have a technical paper available that describes the background of the “Estimate Grain Diameters” algorithm: https://www.math2market.de/fileadmin/Showroom/Technical-Reports/M2M-2021-01_TechReport_Math2Market.pdf
- In the example, I used the options “Chosen Material IDs: 2” (coating’s material ID) and “Remove Grain Fragments at Domain Boundary” (if you leave this checked you will get low coating thickness at the domain boundaries in the result
- [ IMAGE NOT SHOWN - GUESTS CANNOT VIEW ATTACHED IMAGES ]
Finally, you can interpretate the grain diameters as the shell thickness. It can be visualized by the volume field "Diameter".
[ IMAGE NOT SHOWN - GUESTS CANNOT VIEW ATTACHED IMAGES ]
Note: You could use a similar workflow with Analyse -> MatDict -> Material Characterization -> Solid Size Distribution (Granulometry) in the step 2 from above.
- Please note the instruction for Granulometry in the MatDict UserGuide (page 20 and following).
- Especially the bin size must be selected small enough depending on the expected minimum coating thicknesses.
- Different visualization options are described, probably the best for your problem is the volume fraction visualization.
This approach will also fit spheres in the coating material, however corners are a differently treated as in the "Estimate Grain Diameter" approach from above, because smaller spheres are not merged with neighboring large spheres.
I hope my answer helped you.
Best regards, Roman